Given,
Now,
xy + yz + xz
{∵ cos (A + B) = cos A cos B – sin A sin B}
{sin (180° - A) = sin A ; sin (180° + A) = -sin A;
cos (180° - A) = -cos A & cos (180° + A) = -cos A }
= 0
= R.H.S.
Hence Proved